AAlgoLoopSpaced repetition for LeetCode
EASYDesignLeetCode ↗

Implement Stack using Queues

The key idea

A queue is FIFO, but a stack needs LIFO. The trick is to keep the queue's front equal to the stack's top. Right after every push, rotate the older elements behind the new one so the newest value sits at the front — then pop and top are just front operations.

Problem

Implement a last-in-first-out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal stack (push, top, pop, and empty).

Implement the MyStack class:

- void push(int x) Pushes element x onto the top of the stack.
- int pop() Removes the element on the top of the stack and returns it.
- int top() Returns the element on the top of the stack.
- boolean empty() Returns true if the stack is empty, false otherwise.

You must use only standard operations of a queue, which means that only push to back, peek/pop from front, size, and is empty operations are valid. Depending on your language, the queue may not be supported natively. You may simulate a queue using a list or deque (double-ended queue) as long as you use only a queue's standard operations.

Follow-up: Can you implement the stack using only one queue?

Constraints

Examples

Input: ["MyStack", "push", "push", "top", "pop", "empty"] [[], [1], [2], [], [], []] Output: [null, null, null, 2, 2, false]
Input: ["MyStack", "push", "pop", "empty"] [[], [4], [], []] Output: [null, null, 4, true]

Complexity

Time: O(n) push, O(1) pop/top (push-costly variant) Space: O(n)

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