Minimum Genetic Mutation
The key idea
Each gene is a node and a single-character change to another valid bank gene is an edge of weight 1. "Fewest mutations" is therefore the shortest path in an unweighted graph, which BFS finds level by level.
Problem
A gene string can be represented by an 8-character long string, with choices from 'A', 'C', 'G', and 'T'.
Suppose we need to investigate a mutation from a gene string startGene to a gene string endGene where one mutation is defined as one single character changed in the gene string.
There is also a gene bank that records all the valid gene mutations. A gene must be in bank to make it a valid gene string.
Given the two gene strings startGene and endGene and the gene bank, return the minimum number of mutations needed to mutate from startGene to endGene. If there is no such a mutation, return -1.
Note that the starting point is assumed to be valid, so it might not be included in the bank.
Constraints
startGene.length == 8endGene.length == 80 <= bank.length <= 10bank[i].length == 8startGene,endGene, andbank[i]consist of only the characters['A', 'C', 'G', 'T'].
Examples
Input: startGene = "AACCGGTT", endGene = "AACCGGTA", bank = ["AACCGGTA"]
Output: 1
Input: startGene = "AACCGGTT", endGene = "AAACGGTA", bank = ["AACCGGTA","AACCGCTA","AAACGGTA"]
Output: 2
Complexity
Time: O(B * L * 4) Space: O(B)
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