Number of Provinces
The key idea
A province is exactly a connected component of the friendship graph. Count components: start at an unvisited city, flood-fill (DFS/BFS) every city reachable through direct or indirect connections to mark the whole group, and add one to the answer for each fresh flood-fill you launch. Each launch discovers one entire province.
Problem
There are n cities. Some of them are connected, while some are not. If city a is connected directly with city b, and city b is connected directly with city c, then city a is connected indirectly with city c.
A province is a group of directly or indirectly connected cities and no other cities outside of the group.
You are given an n x n matrix isConnected where isConnected[i][j] = 1 if the ith city and the jth city are directly connected, and isConnected[i][j] = 0 otherwise.
Return the total number of provinces.
Constraints
- 1 <= n <= 200
- n == isConnected.length
- n == isConnected[i].length
- isConnected[i][j] is 1 or 0
- isConnected[i][i] == 1
- isConnected[i][j] == isConnected[j][i]
Examples
Input: isConnected = [[1,1,0],[1,1,0],[0,0,1]]
Output: 2
Input: isConnected = [[1,0,0],[0,1,0],[0,0,1]]
Output: 3
Complexity
Time: O(n^2) Space: O(n)
See the full solution
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